We are finally at a point where we can talk about chemical equilibrium we have encountered at the kinetics section. Consider the following reaction,
.
From before, the Helmholtz freee energy is
,
where dNj = vjd
l.
If we keep T and V constant as we do in an experiment, the free energy can be written as
.
At equilibrium, the free energy is zero, therefore we have
![]() | Equilibrium Condition | (1) |
The partition function of the system of mixture of ideal gases should be the product of individual partition function of each reactants and products; it means
.
We will relate chemical potential from Eqn. (1) to the partition function
by
. (2)
Substitute Eqn. (2) into Eqn. (1), we can get
.
Since the partition function is a function of temperature with constant
volume, and therefore q/V which can be considered as a concentration.
Then we have an equilibrium constant as a function of temperature only.
![]() | Concentration Equilibrium Constant | (3) |
![]() | Partial Pressure Equilibrium Constant | (4) |